0.002x=0.001x^2

Solution for 0.002x=0.001x^2 equation:

0.002x=0.001x^2

We move all terms to the left:

0.002x-(0.001x^2)=0

We get rid of parentheses

-0.001x^2+0.002x=0

a = -0.001; b = 0.002; c = 0;
Δ = b2-4ac
Δ = 0.0022-4·(-0.001)·0
Δ = 4.0E-6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.002)-\sqrt{4.0E-6}}{2*-0.001}=\frac{-0.002-\sqrt{4.0E-6}}{-0.002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.002)+\sqrt{4.0E-6}}{2*-0.001}=\frac{-0.002+\sqrt{4.0E-6}}{-0.002}
$